YES
O(n^2)
TRS:
 {   f(0()) -> cons(0()),
  f(s(0())) -> f(p(s(0()))),
  p(s(0())) -> 0()}
 DUP: We consider a non-duplicating system.
  Trs:
   {   f(0()) -> cons(0()),
    f(s(0())) -> f(p(s(0()))),
    p(s(0())) -> 0()}
  Matrix Interpretation:
   Interpretation class: triangular
       [X1]    [1 1][X1]   [0]
   [s]([X0]) = [0 1][X0] + [1]
   
       [X1]    [1 0][X1]   [0]
   [p]([X0]) = [0 0][X0] + [1]
   
       [X1]    [1 1][X1]   [0]
   [f]([X0]) = [0 0][X0] + [0]
   
         [1]
   [0] = [1]
   
          [X1]    [1 0][X1]   [0]
   [cons]([X0]) = [0 0][X0] + [0]
   
   
   Qed