YES
O(n^2)
TRS:
 { f(+(x, 0())) -> f(x),
  +(x, +(y, z)) -> +(+(x, y), z)}
 DUP: We consider a non-duplicating system.
  Trs:
   { f(+(x, 0())) -> f(x),
    +(x, +(y, z)) -> +(+(x, y), z)}
  Matrix Interpretation:
   Interpretation class: triangular
         [1]
   [0] = [0]
   
       [X3]  [X1]    [1 0][X3]   [1 1][X1]   [0]
   [+]([X2], [X0]) = [0 1][X2] + [0 1][X0] + [1]
   
       [X1]    [1 0][X1]   [0]
   [f]([X0]) = [0 0][X0] + [0]
   
   
   Qed