YES
O(n^2)
TRS:
 {
       i(div(X, Y)) -> div(Y, X),
        div(X, e()) -> i(X),
  div(div(X, Y), Z) -> div(Y, div(i(X), Z))
 }
 DUP: We consider a non-duplicating system.
  Trs:
   {
         i(div(X, Y)) -> div(Y, X),
          div(X, e()) -> i(X),
    div(div(X, Y), Z) -> div(Y, div(i(X), Z))
   }
  Matrix Interpretation:
   Interpretation class: triangular
         [1]
   [e] = [0]
   
         [X3]  [X1]    [1 1][X3]   [1 0][X1]   [0]
   [div]([X2], [X0]) = [0 1][X2] + [0 1][X0] + [1]
   
       [X1]    [1 1][X1]   [0]
   [i]([X0]) = [0 1][X0] + [0]
   
   
   Qed