YES
O(n^2)
TRS:
 {
         first(0(), X) -> nil(),
  first(s(X), cons(Y)) -> cons(Y),
               from(X) -> cons(X)
 }
 DUP: We consider a non-duplicating system.
  Trs:
   {
           first(0(), X) -> nil(),
    first(s(X), cons(Y)) -> cons(Y),
                 from(X) -> cons(X)
   }
  Matrix Interpretation:
   Interpretation class: triangular
          [X1]    [1 0][X1]   [1]
   [from]([X0]) = [0 1][X0] + [0]
   
       [X1]    [1 0][X1]   [1]
   [s]([X0]) = [0 0][X0] + [0]
   
          [X1]    [1 0][X1]   [0]
   [cons]([X0]) = [0 0][X0] + [0]
   
         [1]
   [0] = [1]
   
           [X3]  [X1]    [1 1][X3]   [1 0][X1]   [0]
   [first]([X2], [X0]) = [0 0][X2] + [0 0][X0] + [0]
   
           [0]
   [nil] = [0]
   
   
   Qed