YES
O(n^3)
TRS:
 {
     +(x, 0()) -> x,
    +(x, s(y)) -> s(+(x, y)),
  +(0(), s(y)) -> s(y),
  s(+(0(), y)) -> s(y)
 }
 DUP: We consider a non-duplicating system.
  Trs:
   {
       +(x, 0()) -> x,
      +(x, s(y)) -> s(+(x, y)),
    +(0(), s(y)) -> s(y),
    s(+(0(), y)) -> s(y)
   }
  Matrix Interpretation:
   Interpretation class: triangular
       [X2]    [1 0 0][X2]   [0]
   [s]([X1]) = [0 0 0][X1] + [0]
       [X0]    [0 0 1][X0]   [1]
   
         [1]
   [0] = [0]
         [0]
   
       [X5]  [X2]    [1 0 0][X5]   [1 0 1][X2]   [0]
   [+]([X4], [X1]) = [0 1 0][X4] + [0 0 0][X1] + [0]
       [X3]  [X0]    [0 0 1][X3]   [0 0 1][X0]   [0]
   
   
   Qed