YES
O(n^3)
TRS:
 { f(+(x, 0())) -> f(x),
  +(x, +(y, z)) -> +(+(x, y), z)}
 DUP: We consider a non-duplicating system.
  Trs:
   { f(+(x, 0())) -> f(x),
    +(x, +(y, z)) -> +(+(x, y), z)}
  Matrix Interpretation:
   Interpretation class: triangular
         [0]
   [0] = [0]
         [1]
   
       [X5]  [X2]    [1 0 0][X5]   [1 1 0][X2]   [0]
   [+]([X4], [X1]) = [0 1 0][X4] + [0 1 0][X1] + [1]
       [X3]  [X0]    [0 0 1][X3]   [0 0 1][X0]   [0]
   
       [X2]    [1 0 1][X2]   [0]
   [f]([X1]) = [0 0 0][X1] + [0]
       [X0]    [0 0 0][X0]   [0]
   
   
   Qed