YES
O(n^3)
TRS:
 {
      b(y, 0()) -> y,
  c(b(y, c(x))) -> c(c(b(a(0(), 0()), y))),
        a(x, y) -> b(x, b(0(), c(y)))
 }
 DUP: We consider a non-duplicating system.
  Trs:
   {
        b(y, 0()) -> y,
    c(b(y, c(x))) -> c(c(b(a(0(), 0()), y))),
          a(x, y) -> b(x, b(0(), c(y)))
   }
  Matrix Interpretation:
   Interpretation class: triangular
       [X5]  [X2]    [1 0 3][X5]   [1 2 2][X2]   [2]
   [a]([X4], [X1]) = [0 1 2][X4] + [0 0 0][X1] + [1]
       [X3]  [X0]    [0 0 1][X3]   [0 0 0][X0]   [0]
   
       [X2]    [1 2 0][X2]   [0]
   [c]([X1]) = [0 0 0][X1] + [0]
       [X0]    [0 0 0][X0]   [3]
   
         [1]
   [0] = [0]
         [0]
   
       [X5]  [X2]    [1 0 2][X5]   [1 0 0][X2]   [0]
   [b]([X4], [X1]) = [0 1 2][X4] + [0 0 3][X1] + [1]
       [X3]  [X0]    [0 0 1][X3]   [0 0 0][X0]   [0]
   
   
   Qed