YES
O(n^4)
TRS:
 {   f(f(X)) -> f(g(f(g(f(X))))),
  f(g(f(X))) -> f(g(X))}
 DUP: We consider a non-duplicating system.
  Trs:
   {   f(f(X)) -> f(g(f(g(f(X))))),
    f(g(f(X))) -> f(g(X))}
  Matrix Interpretation:
   Interpretation class: triangular
       [X3]    [1 0 0 0][X3]   [0]
       [X2]    [0 0 0 0][X2]   [0]
   [g]([X1]) = [0 0 0 0][X1] + [0]
       [X0]    [0 0 0 0][X0]   [0]
   
       [X3]    [1 0 1 1][X3]   [1]
       [X2]    [0 0 0 0][X2]   [0]
   [f]([X1]) = [0 0 1 1][X1] + [1]
       [X0]    [0 0 0 0][X0]   [1]
   
   
   Qed