YES
O(n^4)
TRS:
 {
      *(x, 0()) -> 0(),
      *(1(), y) -> y,
  *(*(x, y), z) -> *(x, *(y, z)),
     *(i(x), x) -> 1()
 }
 DUP: We consider a non-duplicating system.
  Trs:
   {
        *(x, 0()) -> 0(),
        *(1(), y) -> y,
    *(*(x, y), z) -> *(x, *(y, z)),
       *(i(x), x) -> 1()
   }
  Matrix Interpretation:
   Interpretation class: triangular
         [0]
         [0]
   [0] = [0]
         [0]
   
       [X3]    [1 0 0 0][X3]   [0]
       [X2]    [0 0 0 0][X2]   [0]
   [i]([X1]) = [0 0 0 0][X1] + [0]
       [X0]    [0 0 0 0][X0]   [0]
   
       [X7]  [X3]    [1 1 0 0][X7]   [1 0 0 0][X3]   [1]
       [X6]  [X2]    [0 1 0 0][X6]   [0 1 0 0][X2]   [1]
   [*]([X5], [X1]) = [0 0 0 0][X5] + [0 0 1 0][X1] + [0]
       [X4]  [X0]    [0 0 0 0][X4]   [0 0 0 1][X0]   [0]
   
         [0]
         [0]
   [1] = [0]
         [0]
   
   
   Qed