YES
O(n^5)
TRS:
 {f(s(s(x))) -> f(f(s(x))),
   f(s(0())) -> s(0()),
      f(0()) -> s(0())}
 DUP: We consider a non-duplicating system.
  Trs:
   {f(s(s(x))) -> f(f(s(x))),
     f(s(0())) -> s(0()),
        f(0()) -> s(0())}
  Matrix Interpretation:
   Interpretation class: triangular
       [X4]    [1 0 1 0 0][X4]   [1]
       [X3]    [0 0 1 0 0][X3]   [0]
   [f]([X2]) = [0 0 0 0 0][X2] + [0]
       [X1]    [0 0 0 0 0][X1]   [1]
       [X0]    [0 0 0 0 0][X0]   [1]
   
         [0]
         [0]
   [0] = [0]
         [0]
         [0]
   
       [X4]    [1 0 0 0 0][X4]   [0]
       [X3]    [0 0 0 0 0][X3]   [0]
   [s]([X2]) = [0 0 1 1 1][X2] + [0]
       [X1]    [0 0 0 1 0][X1]   [1]
       [X0]    [0 0 0 0 0][X0]   [1]
   
   
   Qed