YES
O(n^4)
TRS:
 {
       i(div(X, Y)) -> div(Y, X),
        div(X, e()) -> i(X),
  div(div(X, Y), Z) -> div(Y, div(i(X), Z))
 }
 DUP: We consider a non-duplicating system.
  Trs:
   {
         i(div(X, Y)) -> div(Y, X),
          div(X, e()) -> i(X),
    div(div(X, Y), Z) -> div(Y, div(i(X), Z))
   }
  Matrix Interpretation:
   Interpretation class: triangular
         [0]
         [0]
   [e] = [0]
         [0]
   
         [X7]  [X3]    [1 1 0 0][X7]   [1 0 0 0][X3]   [1]
         [X6]  [X2]    [0 1 0 0][X6]   [0 1 0 0][X2]   [1]
   [div]([X5], [X1]) = [0 0 0 0][X5] + [0 0 0 0][X1] + [0]
         [X4]  [X0]    [0 0 0 0][X4]   [0 0 0 0][X0]   [0]
   
       [X3]    [1 1 0 0][X3]   [0]
       [X2]    [0 1 0 0][X2]   [0]
   [i]([X1]) = [0 0 0 0][X1] + [0]
       [X0]    [0 0 0 0][X0]   [0]
   
   
   Qed