YES
O(n^4)
TRS:
 { f(+(x, 0())) -> f(x),
  +(x, +(y, z)) -> +(+(x, y), z)}
 DUP: We consider a non-duplicating system.
  Trs:
   { f(+(x, 0())) -> f(x),
    +(x, +(y, z)) -> +(+(x, y), z)}
  Matrix Interpretation:
   Interpretation class: triangular
         [0]
         [1]
   [0] = [0]
         [0]
   
       [X7]  [X3]    [1 0 0 0][X7]   [1 1 0 1][X3]   [1]
       [X6]  [X2]    [0 1 0 1][X6]   [0 1 1 1][X2]   [0]
   [+]([X5], [X1]) = [0 0 1 1][X5] + [0 0 1 1][X1] + [0]
       [X4]  [X0]    [0 0 0 0][X4]   [0 0 0 0][X0]   [1]
   
       [X3]    [1 0 1 1][X3]   [0]
       [X2]    [0 0 0 0][X2]   [0]
   [f]([X1]) = [0 0 0 0][X1] + [0]
       [X0]    [0 0 0 0][X0]   [0]
   
   
   Qed