YES
O(n^4)
TRS:
 {      *(x, x) -> x,
  *(x, *(y, z)) -> *(*(x, y), z)}
 DUP: We consider a non-duplicating system.
  Trs:
   {      *(x, x) -> x,
    *(x, *(y, z)) -> *(*(x, y), z)}
  Matrix Interpretation:
   Interpretation class: triangular
       [X7]  [X3]    [1 0 0 0][X7]   [1 1 0 0][X3]   [1]
       [X6]  [X2]    [0 1 0 0][X6]   [0 0 0 1][X2]   [1]
   [*]([X5], [X1]) = [0 0 0 0][X5] + [0 0 1 0][X1] + [0]
       [X4]  [X0]    [0 0 0 1][X4]   [0 0 0 1][X0]   [1]
   
   
   Qed