YES
O(n^4)
TRS:
 {f(a(), b()) -> f(a(), c()),
  f(c(), d()) -> f(b(), d())}
 DUP: We consider a non-duplicating system.
  Trs:
   {f(a(), b()) -> f(a(), c()),
    f(c(), d()) -> f(b(), d())}
  Matrix Interpretation:
   Interpretation class: triangular
         [0]
         [0]
   [d] = [0]
         [0]
   
         [0]
         [1]
   [b] = [0]
         [1]
   
         [1]
         [0]
   [c] = [1]
         [0]
   
         [0]
         [0]
   [a] = [0]
         [0]
   
       [X7]  [X3]    [1 0 0 0][X7]   [1 1 0 1][X3]   [0]
       [X6]  [X2]    [0 0 1 0][X6]   [0 0 0 0][X2]   [0]
   [f]([X5], [X1]) = [0 0 0 0][X5] + [0 0 0 0][X1] + [0]
       [X4]  [X0]    [0 0 0 0][X4]   [0 0 0 0][X0]   [0]
   
   
   Qed