YES
O(n^5)
TRS:
 {
      +(0(), y) -> y,
   +(s(x), 0()) -> s(x),
  +(s(x), s(y)) -> s(+(s(x), +(y, 0())))
 }
 DUP: We consider a non-duplicating system.
  Trs:
   {
        +(0(), y) -> y,
     +(s(x), 0()) -> s(x),
    +(s(x), s(y)) -> s(+(s(x), +(y, 0())))
   }
  Matrix Interpretation:
   Interpretation class: triangular
       [X4]    [1 0 0 0 1][X4]   [0]
       [X3]    [0 0 0 1 1][X3]   [1]
   [s]([X2]) = [0 0 0 0 0][X2] + [0]
       [X1]    [0 0 0 1 1][X1]   [1]
       [X0]    [0 0 0 0 0][X0]   [0]
   
         [0]
         [0]
   [0] = [0]
         [0]
         [0]
   
       [X9]  [X4]    [1 0 0 0 0][X9]   [1 1 0 1 0][X4]   [1]
       [X8]  [X3]    [0 0 0 1 0][X8]   [0 1 0 0 0][X3]   [0]
   [+]([X7], [X2]) = [0 0 0 0 0][X7] + [0 0 1 0 0][X2] + [0]
       [X6]  [X1]    [0 0 0 1 0][X6]   [0 0 0 1 0][X1]   [0]
       [X5]  [X0]    [0 0 0 0 0][X5]   [0 0 0 0 1][X0]   [0]
   
   
   Qed