YES
O(n^5)
TRS:
 {a(b(a(x))) -> b(a(b(x)))}
 DUP: We consider a non-duplicating system.
  Trs:
   {a(b(a(x))) -> b(a(b(x)))}
  Matrix Interpretation:
   Interpretation class: triangular
       [X4]    [1 0 0 0 1][X4]   [0]
       [X3]    [0 0 0 0 0][X3]   [0]
   [a]([X2]) = [0 0 0 0 0][X2] + [0]
       [X1]    [0 0 0 0 0][X1]   [1]
       [X0]    [0 0 0 0 0][X0]   [1]
   
       [X4]    [1 0 0 0 0][X4]   [0]
       [X3]    [0 0 0 0 0][X3]   [0]
   [b]([X2]) = [0 0 0 0 0][X2] + [0]
       [X1]    [0 0 0 0 0][X1]   [0]
       [X0]    [0 0 0 0 1][X0]   [0]
   
   
   Qed