YES

This TRS is terminating using the deltasimple interpretation 
f(delta3, X2) =  + 1*X2 + 1 + 1*X2*delta3 + 0*delta3
s(delta2, X1) =  + 1*X1 + 1 + 0*X1*delta2 + 0*delta2
g(delta1, X0) =  + 1*X0 + 0 + 1*X0*delta1 + 0*delta1
0(delta0) =  + 1 + 0*delta0
f_tau_1(delta3) =  + (delta3/(1 + 1 * delta3))
s_tau_1(delta2) =  + (delta2/(1 + 0 * delta2))
g_tau_1(delta1) =  + (delta1/(1 + 1 * delta1))
SUCCESS

Statistics:
Number of monomials: 244