YES

This TRS is terminating using the deltasimple interpretation 
f(delta3, X5, X4) =  + 1*X4 + 1*X5 + 0 + 2*X4*delta3 + 1*X5*delta3 + 0*delta3
empty(delta2) =  + 1 + 0*delta2
cons(delta1, X3, X2) =  + 1*X2 + 0*X3 + 1 + 0*X2*delta1 + 1*X3*delta1 + 0*delta1
g(delta0, X1, X0) =  + 1*X0 + 1*X1 + 0 + 0*X0*delta0 + 1*X1*delta0 + 0*delta0
f_tau_1(delta3) =  + (delta3/(1 + 1 * delta3))
f_tau_2(delta3) =  + (delta3/(1 + 2 * delta3))
cons_tau_1(delta1) =  + (delta1/(0 + 1 * delta1))
cons_tau_2(delta1) =  + (delta1/(1 + 0 * delta1))
g_tau_1(delta0) =  + (delta0/(1 + 1 * delta0))
g_tau_2(delta0) =  + (delta0/(1 + 0 * delta0))
SUCCESS

Statistics:
Number of monomials: 238