YES

This TRS is terminating using the deltasimple interpretation 
f(delta2, X4, X3) =  + 1*X3 + 1*X4 + 0 + 0*X3*delta2 + 2*X4*delta2 + 1*delta2
g(delta1, X2, X1) =  + 1*X1 + 1*X2 + 0 + 0*X1*delta1 + 2*X2*delta1 + 0*delta1
h(delta0, X0) =  + 1*X0 + 1 + 0*X0*delta0 + 0*delta0
f_tau_1(delta2) =  + (delta2/(1 + 2 * delta2))
f_tau_2(delta2) =  + (delta2/(1 + 0 * delta2))
g_tau_1(delta1) =  + (delta1/(1 + 2 * delta1))
g_tau_2(delta1) =  + (delta1/(1 + 0 * delta1))
h_tau_1(delta0) =  + (delta0/(1 + 0 * delta0))
SUCCESS

Statistics:
Number of monomials: 172