YES

This TRS is terminating using the deltasimple interpretation 
f(delta5, X3) =  + 0*X3 + 0 + 1*X3*delta5 + 0*delta5
g(delta4, X2) =  + 0*X2 + 0 + 3*X2*delta4 + 0*delta4
h(delta3, X1) =  + 1*X1 + 0 + 0*X1*delta3 + 2*delta3
a(delta2) =  + 0 + 1*delta2
i(delta1, X0) =  + 1*X0 + 1 + 0*X0*delta1 + 0*delta1
b(delta0) =  + 0 + 0*delta0
f_tau_1(delta5) =  + (delta5/(0 + 1 * delta5))
g_tau_1(delta4) =  + (delta4/(0 + 3 * delta4))
h_tau_1(delta3) =  + (delta3/(1 + 0 * delta3))
i_tau_1(delta1) =  + (delta1/(1 + 0 * delta1))
SUCCESS

Statistics:
Number of monomials: 98