YES

This TRS is terminating using the deltalinear interpretation 
rem(delta6, X7, X6) =  + 1*X6 + 1*X7 + 0 + 0*X6*delta6 + 0*X7*delta6 + 1*delta6
f(delta5, X5, X4) =  + 1*X4 + 0*X5 + 1 + 1*X4*delta5 + 1*X5*delta5 + 1*delta5
g(delta4, X3, X2) =  + 0*X2 + 1*X3 + 1 + 1*X2*delta4 + 0*X3*delta4 + 1*delta4
s(delta3, X1) =  + 1*X1 + 0 + 0*X1*delta3 + 0*delta3
nil(delta2) =  + 1 + 0*delta2
norm(delta1, X0) =  + 0*X0 + 0 + 1*X0*delta1 + 1*delta1
0(delta0) =  + 0 + 0*delta0
rem_tau_1(delta6) =  + 1(delta6/(1 + 0 * delta6))
rem_tau_2(delta6) =  + 1(delta6/(1 + 0 * delta6))
f_tau_1(delta5) =  + 1(delta5/(0 + 1 * delta5))
f_tau_2(delta5) =  + 1(delta5/(1 + 1 * delta5))
g_tau_1(delta4) =  + 1(delta4/(1 + 0 * delta4))
g_tau_2(delta4) =  + 1(delta4/(0 + 1 * delta4))
s_tau_1(delta3) =  + 1(delta3/(1 + 0 * delta3))
norm_tau_1(delta1) =  + 1(delta1/(0 + 1 * delta1))

Time: 0.051148 seconds
SUCCESS

Statistics:
Number of monomials: 376
Last formula building started for bound 1
Last SAT solving started for bound 1