YES

Problem:
 f(c(s(x),y)) -> f(c(x,s(y)))
 f(c(s(x),s(y))) -> g(c(x,y))
 g(c(x,s(y))) -> g(c(s(x),y))
 g(c(s(x),s(y))) -> f(c(x,y))

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [g](x0) = 2x0 + 2,
   
   [f](x0) = 2x0,
   
   [c](x0, x1) = 2x0 + 2x1,
   
   [s](x0) = x0 + 2
  orientation:
   f(c(s(x),y)) = 4x + 4y + 8 >= 4x + 4y + 8 = f(c(x,s(y)))
   
   f(c(s(x),s(y))) = 4x + 4y + 16 >= 4x + 4y + 2 = g(c(x,y))
   
   g(c(x,s(y))) = 4x + 4y + 10 >= 4x + 4y + 10 = g(c(s(x),y))
   
   g(c(s(x),s(y))) = 4x + 4y + 18 >= 4x + 4y = f(c(x,y))
  problem:
   f(c(s(x),y)) -> f(c(x,s(y)))
   g(c(x,s(y))) -> g(c(s(x),y))
  Matrix Interpretation Processor: dim=3
   
   interpretation:
              [1 1 0]  
    [g](x0) = [1 1 0]x0
              [0 0 0]  ,
    
              [1 0 0]     [1]
    [f](x0) = [0 0 0]x0 + [0]
              [0 0 0]     [1],
    
                  [1 1 0]     [1 0 0]  
    [c](x0, x1) = [0 0 0]x0 + [0 0 1]x1
                  [0 0 1]     [0 1 0]  ,
    
                   [0]
    [s](x0) = x0 + [0]
                   [1]
   orientation:
                   [1 1 0]    [1 0 0]    [1]    [1 1 0]    [1 0 0]    [1]               
    f(c(s(x),y)) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x + [0 0 0]y + [0] = f(c(x,s(y)))
                   [0 0 0]    [0 0 0]    [1]    [0 0 0]    [0 0 0]    [1]               
    
                   [1 1 0]    [1 0 1]    [1]    [1 1 0]    [1 0 1]                
    g(c(x,s(y))) = [1 1 0]x + [1 0 1]y + [1] >= [1 1 0]x + [1 0 1]y = g(c(s(x),y))
                   [0 0 0]    [0 0 0]    [0]    [0 0 0]    [0 0 0]                
   problem:
    f(c(s(x),y)) -> f(c(x,s(y)))
   Matrix Interpretation Processor: dim=3
    
    interpretation:
               [1 0 0]     [0]
     [f](x0) = [0 0 0]x0 + [0]
               [0 0 0]     [1],
     
                   [1 0 1]     [1 0 0]     [0]
     [c](x0, x1) = [0 1 0]x0 + [0 0 0]x1 + [0]
                   [0 0 0]     [0 0 0]     [1],
     
               [1 0 0]     [0]
     [s](x0) = [0 0 1]x0 + [0]
               [0 0 1]     [1]
    orientation:
                    [1 0 1]    [1 0 0]    [1]    [1 0 1]    [1 0 0]    [0]               
     f(c(s(x),y)) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x + [0 0 0]y + [0] = f(c(x,s(y)))
                    [0 0 0]    [0 0 0]    [1]    [0 0 0]    [0 0 0]    [1]               
    problem:
     
    Qed