YES

Problem:
 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(x1))))))))))
 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(0(1(2(x1)))))))))))))

Proof:
 String Reversal Processor:
  1(2(1(0(x1)))) -> 2(1(0(2(1(0(1(1(2(1(x1))))))))))
  1(2(1(0(x1)))) -> 2(1(0(2(1(0(2(1(0(1(1(2(1(x1)))))))))))))
  Bounds Processor:
   bound: 2
   enrichment: match
   automaton:
    final states: {12,1}
    transitions:
     21(35) -> 36*
     21(32) -> 33*
     21(27) -> 28*
     21(61) -> 62*
     21(58) -> 59*
     21(53) -> 54*
     11(60) -> 61*
     11(55) -> 56*
     11(112) -> 113*
     11(57) -> 58*
     11(52) -> 53*
     11(54) -> 55*
     11(34) -> 35*
     11(29) -> 30*
     11(31) -> 32*
     11(26) -> 27*
     11(28) -> 29*
     01(30) -> 31*
     01(37) -> 38*
     01(59) -> 60*
     01(56) -> 57*
     01(63) -> 64*
     01(33) -> 34*
     22(87) -> 88*
     22(84) -> 85*
     22(79) -> 80*
     12(80) -> 81*
     12(89) -> 90*
     12(86) -> 87*
     12(81) -> 82*
     12(108) -> 109*
     12(83) -> 84*
     12(78) -> 79*
     f30() -> 2*
     02(82) -> 83*
     02(95) -> 96*
     02(85) -> 86*
     20(14) -> 12*
     20(11) -> 1*
     20(8) -> 9*
     20(3) -> 4*
     10(10) -> 11*
     10(5) -> 6*
     10(7) -> 8*
     10(2) -> 3*
     10(4) -> 5*
     10(13) -> 14*
     00(9) -> 10*
     00(6) -> 7*
     00(1) -> 13*
     1 -> 112,3,5
     6 -> 52*
     9 -> 26*
     12 -> 3,5
     30 -> 108*
     33 -> 89*
     36 -> 113,27,37,6
     37 -> 78*
     38 -> 34*
     62 -> 63,27
     64 -> 60*
     88 -> 90,79,95,53
     90 -> 79*
     96 -> 86*
     109 -> 79*
     113 -> 27*
   problem:
    
   Qed