YES

Problem:
 +(x,+(y,z)) -> +(+(x,y),z)
 +(*(x,y),+(x,z)) -> *(x,+(y,z))
 +(*(x,y),+(*(x,z),u)) -> +(*(x,+(y,z)),u)

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [*](x0, x1) = 6x0 + 4x1 + 4,
   
   [+](x0, x1) = x0 + 4x1 + 2
  orientation:
   +(x,+(y,z)) = x + 4y + 16z + 10 >= x + 4y + 4z + 4 = +(+(x,y),z)
   
   +(*(x,y),+(x,z)) = 10x + 4y + 16z + 14 >= 6x + 4y + 16z + 12 = *(x,+(y,z))
   
   +(*(x,y),+(*(x,z),u)) = 16u + 30x + 4y + 16z + 30 >= 4u + 6x + 4y + 16z + 14 = +(*(x,+(y,z)),u)
  problem:
   
  Qed