YES

Problem:
 sum(0()) -> 0()
 sum(s(x)) -> +(sqr(s(x)),sum(x))
 sqr(x) -> *(x,x)
 sum(s(x)) -> +(*(s(x),s(x)),sum(x))

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [*](x0, x1) = x0 + x1,
   
   [+](x0, x1) = x0 + 2x1,
   
   [sqr](x0) = 2x0,
   
   [s](x0) = 4x0,
   
   [sum](x0) = 5x0,
   
   [0] = 5
  orientation:
   sum(0()) = 25 >= 5 = 0()
   
   sum(s(x)) = 20x >= 18x = +(sqr(s(x)),sum(x))
   
   sqr(x) = 2x >= 2x = *(x,x)
   
   sum(s(x)) = 20x >= 18x = +(*(s(x),s(x)),sum(x))
  problem:
   sum(s(x)) -> +(sqr(s(x)),sum(x))
   sqr(x) -> *(x,x)
   sum(s(x)) -> +(*(s(x),s(x)),sum(x))
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [*](x0, x1) = x0 + x1,
    
    [+](x0, x1) = 2x0 + x1 + 2,
    
    [sqr](x0) = 2x0 + 1,
    
    [s](x0) = 4x0 + 2,
    
    [sum](x0) = 6x0 + 4
   orientation:
    sum(s(x)) = 24x + 16 >= 22x + 16 = +(sqr(s(x)),sum(x))
    
    sqr(x) = 2x + 1 >= 2x = *(x,x)
    
    sum(s(x)) = 24x + 16 >= 22x + 14 = +(*(s(x),s(x)),sum(x))
   problem:
    sum(s(x)) -> +(sqr(s(x)),sum(x))
   Matrix Interpretation Processor: dim=1
    
    interpretation:
     [+](x0, x1) = 2x0 + x1 + 1,
     
     [sqr](x0) = 2x0,
     
     [s](x0) = 3x0 + 1,
     
     [sum](x0) = 6x0 + 1
    orientation:
     sum(s(x)) = 18x + 7 >= 18x + 6 = +(sqr(s(x)),sum(x))
    problem:
     
    Qed