YES

Problem:
 rev(nil()) -> nil()
 rev(.(x,y)) -> ++(rev(y),.(x,nil()))
 car(.(x,y)) -> x
 cdr(.(x,y)) -> y
 null(nil()) -> true()
 null(.(x,y)) -> false()
 ++(nil(),y) -> y
 ++(.(x,y),z) -> .(x,++(y,z))

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [false] = 0,
   
   [true] = 4,
   
   [null](x0) = x0 + 4,
   
   [cdr](x0) = 5x0 + 1,
   
   [car](x0) = 6x0,
   
   [++](x0, x1) = x0 + x1,
   
   [.](x0, x1) = 2x0 + x1 + 3,
   
   [rev](x0) = 2x0,
   
   [nil] = 0
  orientation:
   rev(nil()) = 0 >= 0 = nil()
   
   rev(.(x,y)) = 4x + 2y + 6 >= 2x + 2y + 3 = ++(rev(y),.(x,nil()))
   
   car(.(x,y)) = 12x + 6y + 18 >= x = x
   
   cdr(.(x,y)) = 10x + 5y + 16 >= y = y
   
   null(nil()) = 4 >= 4 = true()
   
   null(.(x,y)) = 2x + y + 7 >= 0 = false()
   
   ++(nil(),y) = y >= y = y
   
   ++(.(x,y),z) = 2x + y + z + 3 >= 2x + y + z + 3 = .(x,++(y,z))
  problem:
   rev(nil()) -> nil()
   null(nil()) -> true()
   ++(nil(),y) -> y
   ++(.(x,y),z) -> .(x,++(y,z))
  Matrix Interpretation Processor: dim=3
   
   interpretation:
             [0]
    [true] = [0]
             [1],
    
                 [1 0 0]  
    [null](x0) = [0 0 0]x0
                 [0 1 0]  ,
    
                   [1 0 0]     [1 1 0]  
    [++](x0, x1) = [1 0 0]x0 + [0 1 0]x1
                   [0 1 0]     [0 0 1]  ,
    
                  [1 0 0]     [1 0 0]     [1]
    [.](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [1]
                  [0 0 0]     [0 0 0]     [0],
    
                [1 0 0]     [0]
    [rev](x0) = [0 0 0]x0 + [1]
                [0 0 0]     [0],
    
            [1]
    [nil] = [1]
            [0]
   orientation:
                 [1]    [1]        
    rev(nil()) = [1] >= [1] = nil()
                 [0]    [0]        
    
                  [1]    [0]         
    null(nil()) = [0] >= [0] = true()
                  [1]    [1]         
    
                  [1 1 0]    [1]         
    ++(nil(),y) = [0 1 0]y + [1] >= y = y
                  [0 0 1]    [1]         
    
                   [1 0 0]    [1 0 0]    [1 1 0]    [1]    [1 0 0]    [1 0 0]    [1 1 0]    [1]               
    ++(.(x,y),z) = [1 0 0]x + [1 0 0]y + [0 1 0]z + [1] >= [0 0 0]x + [0 0 0]y + [0 0 0]z + [1] = .(x,++(y,z))
                   [0 0 0]    [0 0 0]    [0 0 1]    [1]    [0 0 0]    [0 0 0]    [0 0 0]    [0]               
   problem:
    rev(nil()) -> nil()
    ++(.(x,y),z) -> .(x,++(y,z))
   Matrix Interpretation Processor: dim=1
    
    interpretation:
     [++](x0, x1) = x0 + x1,
     
     [.](x0, x1) = x0 + x1 + 3,
     
     [rev](x0) = x0 + 4,
     
     [nil] = 0
    orientation:
     rev(nil()) = 4 >= 0 = nil()
     
     ++(.(x,y),z) = x + y + z + 3 >= x + y + z + 3 = .(x,++(y,z))
    problem:
     ++(.(x,y),z) -> .(x,++(y,z))
    Matrix Interpretation Processor: dim=1
     
     interpretation:
      [++](x0, x1) = 5x0 + x1 + 1,
      
      [.](x0, x1) = 5x0 + x1 + 1
     orientation:
      ++(.(x,y),z) = 25x + 5y + z + 6 >= 5x + 5y + z + 2 = .(x,++(y,z))
     problem:
      
     Qed