YES

Problem:
 f(0(),1(),x) -> f(x,x,x)

Proof:
 DP Processor:
  DPs:
   f#(0(),1(),x) -> f#(x,x,x)
  TRS:
   f(0(),1(),x) -> f(x,x,x)
  EDG Processor:
   DPs:
    f#(0(),1(),x) -> f#(x,x,x)
   TRS:
    f(0(),1(),x) -> f(x,x,x)
   graph:
    
   Qed