YES

Problem:
 h(f(x,y)) -> f(y,f(h(h(x)),a()))

Proof:
 Bounds Processor:
  bound: 1
  enrichment: match
  automaton:
   final states: {1}
   transitions:
    f1(6,10) -> 5*
    f1(9,7) -> 10*
    h1(8) -> 9*
    h1(3) -> 8*
    a1() -> 7*
    f30() -> 3*
    f0(6,6) -> 5*
    f0(3,6) -> 1*
    f0(5,2) -> 6*
    h0(4) -> 5*
    h0(3) -> 4*
    a0() -> 2*
    1 -> 4*
  problem:
   
  Qed