YES

Problem:
 h(f(x,y)) -> f(f(a(),h(h(y))),x)

Proof:
 Bounds Processor:
  bound: 1
  enrichment: match
  automaton:
   final states: {1}
   transitions:
    f1(9,8) -> 10*
    f1(10,6) -> 4*
    a1() -> 9*
    h1(7) -> 8*
    h1(2) -> 7*
    f30() -> 2*
    f0(6,2) -> 1*
    f0(6,6) -> 4*
    f0(5,4) -> 6*
    a0() -> 5*
    h0(2) -> 3*
    h0(3) -> 4*
    1 -> 3*
  problem:
   
  Qed