YES Problem: a(x1) -> x1 a(a(x1)) -> b(x1) b(a(b(x1))) -> a(a(b(b(b(x1))))) Proof: DP Processor: DPs: a#(a(x1)) -> b#(x1) b#(a(b(x1))) -> b#(b(x1)) b#(a(b(x1))) -> b#(b(b(x1))) b#(a(b(x1))) -> a#(b(b(b(x1)))) b#(a(b(x1))) -> a#(a(b(b(b(x1))))) TRS: a(x1) -> x1 a(a(x1)) -> b(x1) b(a(b(x1))) -> a(a(b(b(b(x1))))) TDG Processor: DPs: a#(a(x1)) -> b#(x1) b#(a(b(x1))) -> b#(b(x1)) b#(a(b(x1))) -> b#(b(b(x1))) b#(a(b(x1))) -> a#(b(b(b(x1)))) b#(a(b(x1))) -> a#(a(b(b(b(x1))))) TRS: a(x1) -> x1 a(a(x1)) -> b(x1) b(a(b(x1))) -> a(a(b(b(b(x1))))) graph: b#(a(b(x1))) -> b#(b(b(x1))) -> b#(a(b(x1))) -> a#(a(b(b(b(x1))))) b#(a(b(x1))) -> b#(b(b(x1))) -> b#(a(b(x1))) -> a#(b(b(b(x1)))) b#(a(b(x1))) -> b#(b(b(x1))) -> b#(a(b(x1))) -> b#(b(b(x1))) b#(a(b(x1))) -> b#(b(b(x1))) -> b#(a(b(x1))) -> b#(b(x1)) b#(a(b(x1))) -> b#(b(x1)) -> b#(a(b(x1))) -> a#(a(b(b(b(x1))))) b#(a(b(x1))) -> b#(b(x1)) -> b#(a(b(x1))) -> a#(b(b(b(x1)))) b#(a(b(x1))) -> b#(b(x1)) -> b#(a(b(x1))) -> b#(b(b(x1))) b#(a(b(x1))) -> b#(b(x1)) -> b#(a(b(x1))) -> b#(b(x1)) b#(a(b(x1))) -> a#(b(b(b(x1)))) -> a#(a(x1)) -> b#(x1) b#(a(b(x1))) -> a#(a(b(b(b(x1))))) -> a#(a(x1)) -> b#(x1) a#(a(x1)) -> b#(x1) -> b#(a(b(x1))) -> a#(a(b(b(b(x1))))) a#(a(x1)) -> b#(x1) -> b#(a(b(x1))) -> a#(b(b(b(x1)))) a#(a(x1)) -> b#(x1) -> b#(a(b(x1))) -> b#(b(b(x1))) a#(a(x1)) -> b#(x1) -> b#(a(b(x1))) -> b#(b(x1)) Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> x1 a(a(x1)) -> b(x1) b(a(b(x1))) -> a(a(b(b(b(x1))))) interpretation: [b#](x0) = [0 0]x0 + [0], [a#](x0) = [0 3]x0 + [0], [0 0] [-&] [b](x0) = [0 0]x0 + [1 ], [0 3] [1] [a](x0) = [0 0]x0 + [0] orientation: a#(a(x1)) = [3 3]x1 + [3] >= [0 0]x1 + [0] = b#(x1) b#(a(b(x1))) = [3 3]x1 + [4] >= [0 0]x1 + [1] = b#(b(x1)) b#(a(b(x1))) = [3 3]x1 + [4] >= [0 0]x1 + [1] = b#(b(b(x1))) b#(a(b(x1))) = [3 3]x1 + [4] >= [3 3]x1 + [4] = a#(b(b(b(x1)))) b#(a(b(x1))) = [3 3]x1 + [4] >= [3 3]x1 + [4] = a#(a(b(b(b(x1))))) [0 3] [1] a(x1) = [0 0]x1 + [0] >= x1 = x1 [3 3] [3] [0 0] [-&] a(a(x1)) = [0 3]x1 + [1] >= [0 0]x1 + [1 ] = b(x1) [3 3] [4] [3 3] [4] b(a(b(x1))) = [3 3]x1 + [4] >= [3 3]x1 + [4] = a(a(b(b(b(x1))))) problem: DPs: b#(a(b(x1))) -> a#(b(b(b(x1)))) b#(a(b(x1))) -> a#(a(b(b(b(x1))))) TRS: a(x1) -> x1 a(a(x1)) -> b(x1) b(a(b(x1))) -> a(a(b(b(b(x1))))) Restore Modifier: DPs: b#(a(b(x1))) -> a#(b(b(b(x1)))) b#(a(b(x1))) -> a#(a(b(b(b(x1))))) TRS: a(x1) -> x1 a(a(x1)) -> b(x1) b(a(b(x1))) -> a(a(b(b(b(x1))))) EDG Processor: DPs: b#(a(b(x1))) -> a#(b(b(b(x1)))) b#(a(b(x1))) -> a#(a(b(b(b(x1))))) TRS: a(x1) -> x1 a(a(x1)) -> b(x1) b(a(b(x1))) -> a(a(b(b(b(x1))))) graph: Qed