YES Problem: a(x1) -> x1 a(b(x1)) -> b(a(c(x1))) b(x1) -> x1 c(c(x1)) -> b(b(a(x1))) Proof: String Reversal Processor: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(b(x1))) DP Processor: DPs: b#(a(x1)) -> b#(x1) b#(a(x1)) -> a#(b(x1)) b#(a(x1)) -> c#(a(b(x1))) c#(c(x1)) -> b#(x1) c#(c(x1)) -> b#(b(x1)) c#(c(x1)) -> a#(b(b(x1))) TRS: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(b(x1))) TDG Processor: DPs: b#(a(x1)) -> b#(x1) b#(a(x1)) -> a#(b(x1)) b#(a(x1)) -> c#(a(b(x1))) c#(c(x1)) -> b#(x1) c#(c(x1)) -> b#(b(x1)) c#(c(x1)) -> a#(b(b(x1))) TRS: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(b(x1))) graph: c#(c(x1)) -> b#(b(x1)) -> b#(a(x1)) -> c#(a(b(x1))) c#(c(x1)) -> b#(b(x1)) -> b#(a(x1)) -> a#(b(x1)) c#(c(x1)) -> b#(b(x1)) -> b#(a(x1)) -> b#(x1) c#(c(x1)) -> b#(x1) -> b#(a(x1)) -> c#(a(b(x1))) c#(c(x1)) -> b#(x1) -> b#(a(x1)) -> a#(b(x1)) c#(c(x1)) -> b#(x1) -> b#(a(x1)) -> b#(x1) b#(a(x1)) -> c#(a(b(x1))) -> c#(c(x1)) -> a#(b(b(x1))) b#(a(x1)) -> c#(a(b(x1))) -> c#(c(x1)) -> b#(b(x1)) b#(a(x1)) -> c#(a(b(x1))) -> c#(c(x1)) -> b#(x1) b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> c#(a(b(x1))) b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> a#(b(x1)) b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> b#(x1) SCC Processor: #sccs: 1 #rules: 4 #arcs: 12/36 DPs: c#(c(x1)) -> b#(b(x1)) b#(a(x1)) -> b#(x1) b#(a(x1)) -> c#(a(b(x1))) c#(c(x1)) -> b#(x1) TRS: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(b(x1))) Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(b(x1))) interpretation: [c#](x0) = [0 -&]x0 + [0], [b#](x0) = [0 1]x0, [0 2] [0 ] [c](x0) = [0 0]x0 + [-&], [0 2 ] [0 ] [b](x0) = [-& 0 ]x0 + [-&], [0 0] [0] [a](x0) = [0 2]x0 + [0] orientation: c#(c(x1)) = [0 2]x1 + [0] >= [0 2]x1 + [0] = b#(b(x1)) b#(a(x1)) = [1 3]x1 + [1] >= [0 1]x1 = b#(x1) b#(a(x1)) = [1 3]x1 + [1] >= [0 2]x1 + [0] = c#(a(b(x1))) c#(c(x1)) = [0 2]x1 + [0] >= [0 1]x1 = b#(x1) [0 0] [0] a(x1) = [0 2]x1 + [0] >= x1 = x1 [2 4] [2] [2 4] [2] b(a(x1)) = [0 2]x1 + [0] >= [0 2]x1 + [0] = c(a(b(x1))) [0 2 ] [0 ] b(x1) = [-& 0 ]x1 + [-&] >= x1 = x1 [2 2] [0] [0 2] [0] c(c(x1)) = [0 2]x1 + [0] >= [0 2]x1 + [0] = a(b(b(x1))) problem: DPs: c#(c(x1)) -> b#(b(x1)) c#(c(x1)) -> b#(x1) TRS: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(b(x1))) Restore Modifier: DPs: c#(c(x1)) -> b#(b(x1)) c#(c(x1)) -> b#(x1) TRS: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(b(x1))) EDG Processor: DPs: c#(c(x1)) -> b#(b(x1)) c#(c(x1)) -> b#(x1) TRS: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(b(x1))) graph: Qed