YES

Problem:
 a(a(b(a(a(b(a(x1))))))) -> a(b(a(a(b(a(a(a(b(x1)))))))))

Proof:
 String Reversal Processor:
  a(b(a(a(b(a(a(x1))))))) -> b(a(a(a(b(a(a(b(a(x1)))))))))
  Bounds Processor:
   bound: 2
   enrichment: match
   automaton:
    final states: {1}
    transitions:
     b1(55) -> 56*
     b1(45) -> 46*
     b1(25) -> 26*
     b1(87) -> 88*
     b1(52) -> 53*
     b1(42) -> 43*
     b1(22) -> 23*
     b1(59) -> 60*
     b1(49) -> 50*
     b1(29) -> 30*
     b1(83) -> 84*
     b1(80) -> 81*
     a1(82) -> 83*
     a1(57) -> 58*
     a1(47) -> 48*
     a1(27) -> 28*
     a1(84) -> 85*
     a1(54) -> 55*
     a1(44) -> 45*
     a1(24) -> 25*
     a1(86) -> 87*
     a1(81) -> 82*
     a1(56) -> 57*
     a1(51) -> 52*
     a1(46) -> 47*
     a1(41) -> 42*
     a1(26) -> 27*
     a1(21) -> 22*
     a1(58) -> 59*
     a1(53) -> 54*
     a1(48) -> 49*
     a1(43) -> 44*
     a1(28) -> 29*
     a1(23) -> 24*
     a1(85) -> 86*
     b2(127) -> 128*
     b2(97) -> 98*
     b2(123) -> 124*
     b2(93) -> 94*
     b2(120) -> 121*
     b2(90) -> 91*
     a2(122) -> 123*
     a2(92) -> 93*
     a2(124) -> 125*
     a2(119) -> 120*
     a2(94) -> 95*
     a2(89) -> 90*
     a2(126) -> 127*
     a2(121) -> 122*
     a2(96) -> 97*
     a2(91) -> 92*
     a2(125) -> 126*
     a2(95) -> 96*
     f20() -> 2*
     b0(10) -> 1*
     b0(6) -> 7*
     b0(3) -> 4*
     a0(5) -> 6*
     a0(7) -> 8*
     a0(2) -> 3*
     a0(9) -> 10*
     a0(4) -> 5*
     a0(8) -> 9*
     1 -> 42,52,3,5,8
     4 -> 41*
     7 -> 51*
     8 -> 21*
     30 -> 6,22,9
     50 -> 24*
     53 -> 89*
     56 -> 119*
     58 -> 80*
     60 -> 27*
     88 -> 10*
     98 -> 82*
     128 -> 85*
   problem:
    
   Qed