NO

Problem:
 c(a(b(a(x1)))) -> a(b(a(b(c(c(a(x1)))))))

Proof:
 Unfolding Processor:
  loop length: 4
  terms:
   c(a(b(a(b(a(b(a(x58))))))))
   a(b(a(b(c(c(a(b(a(b(a(x58)))))))))))
   a(b(a(b(c(a(b(a(b(c(c(a(b(a(x58))))))))))))))
   a(b(a(b(c(a(b(a(b(c(a(b(a(b(c(c(a(x58)))))))))))))))))
  context: a(b(a(b([]))))
  substitution:
   x58 -> b(c(c(a(b(c(c(a(x58))))))))
  Qed