YES

Problem:
 c(a(b(a(x1)))) -> a(b(a(a(c(a(b(c(a(b(x1))))))))))

Proof:
 String Reversal Processor:
  a(b(a(c(x1)))) -> b(a(c(b(a(c(a(a(b(a(x1))))))))))
  Bounds Processor:
   bound: 2
   enrichment: match
   automaton:
    final states: {1}
    transitions:
     f30() -> 2*
     b0(11) -> 1*
     b0(8) -> 9*
     b0(3) -> 4*
     a0(10) -> 11*
     a0(5) -> 6*
     a0(7) -> 8*
     a0(2) -> 3*
     a0(4) -> 5*
     c0(9) -> 10*
     c0(6) -> 7*
     b1(54) -> 55*
     b1(51) -> 52*
     b1(46) -> 47*
     b1(21) -> 22*
     b1(18) -> 19*
     b1(13) -> 14*
     a1(50) -> 51*
     a1(45) -> 46*
     a1(20) -> 21*
     a1(15) -> 16*
     a1(47) -> 48*
     a1(17) -> 18*
     a1(12) -> 13*
     a1(14) -> 15*
     a1(53) -> 54*
     a1(48) -> 49*
     c1(52) -> 53*
     c1(49) -> 50*
     c1(19) -> 20*
     c1(16) -> 17*
     b2(65) -> 66*
     b2(62) -> 63*
     b2(57) -> 58*
     b2(98) -> 99*
     b2(95) -> 96*
     b2(90) -> 91*
     a2(97) -> 98*
     a2(92) -> 93*
     a2(94) -> 95*
     a2(89) -> 90*
     a2(64) -> 65*
     a2(59) -> 60*
     a2(91) -> 92*
     a2(61) -> 62*
     a2(56) -> 57*
     a2(58) -> 59*
     c2(60) -> 61*
     c2(96) -> 97*
     c2(93) -> 94*
     c2(63) -> 64*
     1 -> 3,5
     6 -> 45*
     9 -> 12*
     16 -> 89*
     19 -> 56*
     22 -> 6*
     55 -> 13*
     66 -> 46*
     99 -> 57*
   problem:
    
   Qed