YES

Problem:
 b(c(a(b(b(c(x1)))))) -> a(b(c(b(b(c(a(x1)))))))

Proof:
 String Reversal Processor:
  c(b(b(a(c(b(x1)))))) -> a(c(b(b(c(b(a(x1)))))))
  Bounds Processor:
   bound: 0
   enrichment: match
   automaton:
    final states: {1}
    transitions:
     f30() -> 2*
     a0(2) -> 3*
     a0(8) -> 1*
     c0(7) -> 8*
     c0(4) -> 5*
     b0(5) -> 6*
     b0(6) -> 7*
     b0(3) -> 4*
   problem:
    
   Qed