YES Problem: 0(*(x1)) -> *(1(x1)) 1(*(x1)) -> 0(#(x1)) #(0(x1)) -> 0(#(x1)) #(1(x1)) -> 1(#(x1)) #($(x1)) -> *($(x1)) #(#(x1)) -> #(x1) #(*(x1)) -> *(x1) Proof: Arctic Interpretation Processor: dimension: 2 interpretation: [2 -&] [$](x0) = [2 0 ]x0, [0 3 ] [#](x0) = [-& 2 ]x0, [0 2] [1](x0) = [0 2]x0, [1 2 ] [0](x0) = [-& 2 ]x0, [2 -&] [*](x0) = [0 2 ]x0 orientation: [3 4] [2 4] 0(*(x1)) = [2 4]x1 >= [2 4]x1 = *(1(x1)) [2 4] [1 4 ] 1(*(x1)) = [2 4]x1 >= [-& 4 ]x1 = 0(#(x1)) [1 5 ] [1 4 ] #(0(x1)) = [-& 4 ]x1 >= [-& 4 ]x1 = 0(#(x1)) [3 5] [0 4] #(1(x1)) = [2 4]x1 >= [0 4]x1 = 1(#(x1)) [5 3] [4 -&] #($(x1)) = [4 2]x1 >= [4 2 ]x1 = *($(x1)) [0 5 ] [0 3 ] #(#(x1)) = [-& 4 ]x1 >= [-& 2 ]x1 = #(x1) [3 5] [2 -&] #(*(x1)) = [2 4]x1 >= [0 2 ]x1 = *(x1) problem: 0(*(x1)) -> *(1(x1)) 1(*(x1)) -> 0(#(x1)) #(0(x1)) -> 0(#(x1)) #(1(x1)) -> 1(#(x1)) #($(x1)) -> *($(x1)) #(#(x1)) -> #(x1) Arctic Interpretation Processor: dimension: 1 interpretation: [$](x0) = 1x0, [#](x0) = 8x0, [1](x0) = 2x0, [0](x0) = 2x0, [*](x0) = 8x0 orientation: 0(*(x1)) = 10x1 >= 10x1 = *(1(x1)) 1(*(x1)) = 10x1 >= 10x1 = 0(#(x1)) #(0(x1)) = 10x1 >= 10x1 = 0(#(x1)) #(1(x1)) = 10x1 >= 10x1 = 1(#(x1)) #($(x1)) = 9x1 >= 9x1 = *($(x1)) #(#(x1)) = 16x1 >= 8x1 = #(x1) problem: 0(*(x1)) -> *(1(x1)) 1(*(x1)) -> 0(#(x1)) #(0(x1)) -> 0(#(x1)) #(1(x1)) -> 1(#(x1)) #($(x1)) -> *($(x1)) KBO Processor: weight function: w0 = 1 w($) = w(#) = w(1) = w(0) = w(*) = 1 precedence: # > 1 > 0 > $ ~ * problem: Qed