YES

Problem:
 .(.(x,y),z) -> .(x,.(y,z))

Proof:
 DP Processor:
  DPs:
   .#(.(x,y),z) -> .#(y,z)
   .#(.(x,y),z) -> .#(x,.(y,z))
  TRS:
   .(.(x,y),z) -> .(x,.(y,z))
  CDG Processor:
   DPs:
    .#(.(x,y),z) -> .#(y,z)
    .#(.(x,y),z) -> .#(x,.(y,z))
   TRS:
    .(.(x,y),z) -> .(x,.(y,z))
   graph:
    
   Qed