YES

Problem:
 p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(b(x2),a(a(b(x1)))),p(x3,x0))

Proof:
 DP Processor:
  DPs:
   p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0)
   p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(b(x2),a(a(b(x1))))
   p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
  TRS:
   p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(b(x2),a(a(b(x1)))),p(x3,x0))
  EDG Processor:
   DPs:
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0)
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(b(x2),a(a(b(x1))))
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
   TRS:
    p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(b(x2),a(a(b(x1)))),p(x3,x0))
   graph:
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0)) ->
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0)
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0)) ->
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(b(x2),a(a(b(x1))))
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0)) ->
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0) ->
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0)
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0) ->
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(b(x2),a(a(b(x1))))
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0) ->
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
   SCC Processor:
    #sccs: 1
    #rules: 2
    #arcs: 6/9
    DPs:
     p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
     p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0)
    TRS:
     p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(b(x2),a(a(b(x1)))),p(x3,x0))
    Matrix Interpretation Processor: dim=3
     
     interpretation:
      [p#](x0, x1) = [0 0 1]x0 + [1 0 1]x1,
      
                    [0 0 1]     [1 1 1]  
      [p](x0, x1) = [0 0 0]x0 + [0 0 0]x1
                    [0 1 0]     [0 0 0]  ,
      
                [0 0 0]  
      [b](x0) = [0 1 1]x0
                [0 1 0]  ,
      
                [0 0 0]     [0]
      [a](x0) = [0 0 0]x0 + [1]
                [1 1 1]     [1]
     orientation:
      p#(p(b(a(x0)),x1),p(x2,x3)) = [1 1 1]x0 + [0 1 1]x2 + [1 1 1]x3 + [2] >= [1 1 1]x0 + [0 1 1]x2 + [0 1 1]x3 = p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
      
      p#(p(b(a(x0)),x1),p(x2,x3)) = [1 1 1]x0 + [0 1 1]x2 + [1 1 1]x3 + [2] >= [1 0 1]x0 + [0 0 1]x3 = p#(x3,x0)
      
                                   [1 1 1]     [0 1 1]     [1 1 1]     [2]    [1 1 1]     [0 1 1]     [0 1 1]                                     
      p(p(b(a(x0)),x1),p(x2,x3)) = [0 0 0]x0 + [0 0 0]x2 + [0 0 0]x3 + [0] >= [0 0 0]x0 + [0 0 0]x2 + [0 0 0]x3 = p(p(b(x2),a(a(b(x1)))),p(x3,x0))
                                   [0 0 0]     [0 0 0]     [0 0 0]     [0]    [0 0 0]     [0 0 0]     [0 0 0]                                     
     problem:
      DPs:
       
      TRS:
       p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(b(x2),a(a(b(x1)))),p(x3,x0))
     Qed