YES

Problem:
 0(1(2(3(4(5(1(x1))))))) -> 1(2(3(4(5(1(1(0(1(2(3(4(5(0(1(2(3(4(5(x1)))))))))))))))))))
 0(1(2(3(4(5(1(x1))))))) ->
 1(2(3(4(5(1(1(0(1(2(3(4(5(0(1(2(3(4(5(0(1(2(3(4(5(x1)))))))))))))))))))))))))

Proof:
 DP Processor:
  DPs:
   0#(1(2(3(4(5(1(x1))))))) -> 0#(1(2(3(4(5(x1))))))
   0#(1(2(3(4(5(1(x1))))))) -> 0#(1(2(3(4(5(0(1(2(3(4(5(x1))))))))))))
   0#(1(2(3(4(5(1(x1))))))) -> 0#(1(2(3(4(5(0(1(2(3(4(5(0(1(2(3(4(5(x1))))))))))))))))))
  TRS:
   0(1(2(3(4(5(1(x1))))))) -> 1(2(3(4(5(1(1(0(1(2(3(4(5(0(1(2(3(4(5(x1)))))))))))))))))))
   0(1(2(3(4(5(1(x1))))))) ->
   1(2(3(4(5(1(1(0(1(2(3(4(5(0(1(2(3(4(5(0(1(2(3(4(5(x1)))))))))))))))))))))))))
  Matrix Interpretation Processor: dim=2
   
   interpretation:
    [0#](x0) = [2 2]x0,
    
              [2 0]     [3]
    [0](x0) = [1 0]x0 + [0],
    
              [1 0]  
    [2](x0) = [0 0]x0,
    
              [1 0]  
    [3](x0) = [1 1]x0,
    
                
    [4](x0) = x0,
    
              [0 1]  
    [5](x0) = [1 0]x0,
    
              [1 0]     [0]
    [1](x0) = [0 2]x0 + [1]
   orientation:
    0#(1(2(3(4(5(1(x1))))))) = [0 4]x1 + [4] >= [0 2]x1 + [2] = 0#(1(2(3(4(5(x1))))))
    
    0#(1(2(3(4(5(1(x1))))))) = [0 4]x1 + [4] >= [0 2]x1 + [2] = 0#(1(2(3(4(5(0(1(2(3(4(5(x1))))))))))))
    
    0#(1(2(3(4(5(1(x1))))))) = [0 4]x1 + [4] >= [0 2]x1 + [2] = 0#(1(2(3(4(5(0(1(2(3(4(5(0(1(2(3(4(5(x1))))))))))))))))))
    
                              [0 4]     [5]    [0 4]     [3]                                                              
    0(1(2(3(4(5(1(x1))))))) = [0 2]x1 + [1] >= [0 0]x1 + [1] = 1(2(3(4(5(1(1(0(1(2(3(4(5(0(1(2(3(4(5(x1)))))))))))))))))))
    
                              [0 4]     [5]    [0 4]     [3]                                                                                
    0(1(2(3(4(5(1(x1))))))) = [0 2]x1 + [1] >= [0 0]x1 + [1] = 1(2(3(4(5(1(1(0(1(2(3(4(5(0(1(2(3(4(5(0(1(2(3(4(5(x1)))))))))))))))))))))))))
   problem:
    DPs:
     
    TRS:
     0(1(2(3(4(5(1(x1))))))) -> 1(2(3(4(5(1(1(0(1(2(3(4(5(0(1(2(3(4(5(x1)))))))))))))))))))
     0(1(2(3(4(5(1(x1))))))) ->
     1(2(3(4(5(1(1(0(1(2(3(4(5(0(1(2(3(4(5(0(1(2(3(4(5(x1)))))))))))))))))))))))))
   Qed