YES

Problem:
 *(x,*(y,z)) -> *(*(x,y),z)
 *(x,x) -> x

Proof:
 DP Processor:
  DPs:
   *#(x,*(y,z)) -> *#(x,y)
   *#(x,*(y,z)) -> *#(*(x,y),z)
  TRS:
   *(x,*(y,z)) -> *(*(x,y),z)
   *(x,x) -> x
  CDG Processor:
   DPs:
    *#(x,*(y,z)) -> *#(x,y)
    *#(x,*(y,z)) -> *#(*(x,y),z)
   TRS:
    *(x,*(y,z)) -> *(*(x,y),z)
    *(x,x) -> x
   graph:
    
   Qed