YES

Problem:
 b(a(b(c(c(b(x1)))))) -> a(b(b(c(c(b(a(x1)))))))

Proof:
 DP Processor:
  DPs:
   b#(a(b(c(c(b(x1)))))) -> b#(a(x1))
   b#(a(b(c(c(b(x1)))))) -> b#(c(c(b(a(x1)))))
   b#(a(b(c(c(b(x1)))))) -> b#(b(c(c(b(a(x1))))))
  TRS:
   b(a(b(c(c(b(x1)))))) -> a(b(b(c(c(b(a(x1)))))))
  EDG Processor:
   DPs:
    b#(a(b(c(c(b(x1)))))) -> b#(a(x1))
    b#(a(b(c(c(b(x1)))))) -> b#(c(c(b(a(x1)))))
    b#(a(b(c(c(b(x1)))))) -> b#(b(c(c(b(a(x1))))))
   TRS:
    b(a(b(c(c(b(x1)))))) -> a(b(b(c(c(b(a(x1)))))))
   graph:
    b#(a(b(c(c(b(x1)))))) -> b#(a(x1)) ->
    b#(a(b(c(c(b(x1)))))) -> b#(a(x1))
    b#(a(b(c(c(b(x1)))))) -> b#(a(x1)) ->
    b#(a(b(c(c(b(x1)))))) -> b#(c(c(b(a(x1)))))
    b#(a(b(c(c(b(x1)))))) -> b#(a(x1)) -> b#(a(b(c(c(b(x1)))))) -> b#(b(c(c(b(a(x1))))))
   CDG Processor:
    DPs:
     b#(a(b(c(c(b(x1)))))) -> b#(a(x1))
     b#(a(b(c(c(b(x1)))))) -> b#(c(c(b(a(x1)))))
     b#(a(b(c(c(b(x1)))))) -> b#(b(c(c(b(a(x1))))))
    TRS:
     b(a(b(c(c(b(x1)))))) -> a(b(b(c(c(b(a(x1)))))))
    graph:
     
    Qed