YES

Problem:
 app(nil(),y) -> y
 app(add(n,x),y) -> add(n,app(x,y))
 reverse(nil()) -> nil()
 reverse(add(n,x)) -> app(reverse(x),add(n,nil()))
 shuffle(nil()) -> nil()
 shuffle(add(n,x)) -> add(n,shuffle(reverse(x)))

Proof:
 DP Processor:
  DPs:
   app#(add(n,x),y) -> app#(x,y)
   reverse#(add(n,x)) -> reverse#(x)
   reverse#(add(n,x)) -> app#(reverse(x),add(n,nil()))
   shuffle#(add(n,x)) -> reverse#(x)
   shuffle#(add(n,x)) -> shuffle#(reverse(x))
  TRS:
   app(nil(),y) -> y
   app(add(n,x),y) -> add(n,app(x,y))
   reverse(nil()) -> nil()
   reverse(add(n,x)) -> app(reverse(x),add(n,nil()))
   shuffle(nil()) -> nil()
   shuffle(add(n,x)) -> add(n,shuffle(reverse(x)))
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [shuffle#](x0) = x0 + 2,
    
    [reverse#](x0) = x0 + 2,
    
    [app#](x0, x1) = x0 + x1 + 1,
    
    [shuffle](x0) = 4x0 + 7,
    
    [reverse](x0) = x0,
    
    [add](x0, x1) = 2x0 + x1 + 1,
    
    [app](x0, x1) = x0 + x1,
    
    [nil] = 0
   orientation:
    app#(add(n,x),y) = 2n + x + y + 2 >= x + y + 1 = app#(x,y)
    
    reverse#(add(n,x)) = 2n + x + 3 >= x + 2 = reverse#(x)
    
    reverse#(add(n,x)) = 2n + x + 3 >= 2n + x + 2 = app#(reverse(x),add(n,nil()))
    
    shuffle#(add(n,x)) = 2n + x + 3 >= x + 2 = reverse#(x)
    
    shuffle#(add(n,x)) = 2n + x + 3 >= x + 2 = shuffle#(reverse(x))
    
    app(nil(),y) = y >= y = y
    
    app(add(n,x),y) = 2n + x + y + 1 >= 2n + x + y + 1 = add(n,app(x,y))
    
    reverse(nil()) = 0 >= 0 = nil()
    
    reverse(add(n,x)) = 2n + x + 1 >= 2n + x + 1 = app(reverse(x),add(n,nil()))
    
    shuffle(nil()) = 7 >= 0 = nil()
    
    shuffle(add(n,x)) = 8n + 4x + 11 >= 2n + 4x + 8 = add(n,shuffle(reverse(x)))
   problem:
    DPs:
     
    TRS:
     app(nil(),y) -> y
     app(add(n,x),y) -> add(n,app(x,y))
     reverse(nil()) -> nil()
     reverse(add(n,x)) -> app(reverse(x),add(n,nil()))
     shuffle(nil()) -> nil()
     shuffle(add(n,x)) -> add(n,shuffle(reverse(x)))
   Qed