YES

Problem:
 +(0(),y) -> y
 +(s(x),y) -> s(+(x,y))
 -(0(),y) -> 0()
 -(x,0()) -> x
 -(s(x),s(y)) -> -(x,y)

Proof:
 DP Processor:
  DPs:
   +#(s(x),y) -> +#(x,y)
   -#(s(x),s(y)) -> -#(x,y)
  TRS:
   +(0(),y) -> y
   +(s(x),y) -> s(+(x,y))
   -(0(),y) -> 0()
   -(x,0()) -> x
   -(s(x),s(y)) -> -(x,y)
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [-#](x0, x1) = 4x0 + 5x1,
    
    [+#](x0, x1) = x0 + 4,
    
    [-](x0, x1) = 4x0,
    
    [s](x0) = x0 + 1,
    
    [+](x0, x1) = 4x0 + x1,
    
    [0] = 0
   orientation:
    +#(s(x),y) = x + 5 >= x + 4 = +#(x,y)
    
    -#(s(x),s(y)) = 4x + 5y + 9 >= 4x + 5y = -#(x,y)
    
    +(0(),y) = y >= y = y
    
    +(s(x),y) = 4x + y + 4 >= 4x + y + 1 = s(+(x,y))
    
    -(0(),y) = 0 >= 0 = 0()
    
    -(x,0()) = 4x >= x = x
    
    -(s(x),s(y)) = 4x + 4 >= 4x = -(x,y)
   problem:
    DPs:
     
    TRS:
     +(0(),y) -> y
     +(s(x),y) -> s(+(x,y))
     -(0(),y) -> 0()
     -(x,0()) -> x
     -(s(x),s(y)) -> -(x,y)
   Qed