YES

Problem:
 t(o(x1)) -> m(a(x1))
 t(e(x1)) -> n(s(x1))
 a(l(x1)) -> a(t(x1))
 o(m(a(x1))) -> t(e(n(x1)))
 s(a(x1)) -> l(a(t(o(m(a(t(e(x1))))))))
 n(s(x1)) -> a(l(a(t(x1))))

Proof:
 DP Processor:
  DPs:
   t#(o(x1)) -> a#(x1)
   t#(e(x1)) -> s#(x1)
   t#(e(x1)) -> n#(s(x1))
   a#(l(x1)) -> t#(x1)
   a#(l(x1)) -> a#(t(x1))
   o#(m(a(x1))) -> n#(x1)
   o#(m(a(x1))) -> t#(e(n(x1)))
   s#(a(x1)) -> t#(e(x1))
   s#(a(x1)) -> a#(t(e(x1)))
   s#(a(x1)) -> o#(m(a(t(e(x1)))))
   s#(a(x1)) -> t#(o(m(a(t(e(x1))))))
   s#(a(x1)) -> a#(t(o(m(a(t(e(x1)))))))
   n#(s(x1)) -> t#(x1)
   n#(s(x1)) -> a#(t(x1))
   n#(s(x1)) -> a#(l(a(t(x1))))
  TRS:
   t(o(x1)) -> m(a(x1))
   t(e(x1)) -> n(s(x1))
   a(l(x1)) -> a(t(x1))
   o(m(a(x1))) -> t(e(n(x1)))
   s(a(x1)) -> l(a(t(o(m(a(t(e(x1))))))))
   n(s(x1)) -> a(l(a(t(x1))))
  Matrix Interpretation Processor: dim=2
   
   interpretation:
    [o#](x0) = [1 0]x0 + [5],
    
    [n#](x0) = [0 2]x0,
    
    [s#](x0) = [2 1]x0 + [3],
    
    [a#](x0) = [1 0]x0,
    
    [t#](x0) = [0 2]x0 + [1],
    
              [0 4]     [2]
    [l](x0) = [0 0]x0 + [0],
    
              [0 2]  
    [n](x0) = [0 0]x0,
    
              [0 1]     [4]
    [s](x0) = [1 1]x0 + [2],
    
              [0 0]     [0]
    [e](x0) = [1 2]x0 + [2],
    
              [0 1]     [1]
    [m](x0) = [0 0]x0 + [0],
    
              [1 0]     [2]
    [a](x0) = [0 4]x0 + [0],
    
              [0 2]  
    [t](x0) = [0 0]x0,
    
              [1 0]     [4]
    [o](x0) = [1 2]x0 + [1]
   orientation:
    t#(o(x1)) = [2 4]x1 + [3] >= [1 0]x1 = a#(x1)
    
    t#(e(x1)) = [2 4]x1 + [5] >= [2 1]x1 + [3] = s#(x1)
    
    t#(e(x1)) = [2 4]x1 + [5] >= [2 2]x1 + [4] = n#(s(x1))
    
    a#(l(x1)) = [0 4]x1 + [2] >= [0 2]x1 + [1] = t#(x1)
    
    a#(l(x1)) = [0 4]x1 + [2] >= [0 2]x1 = a#(t(x1))
    
    o#(m(a(x1))) = [0 4]x1 + [6] >= [0 2]x1 = n#(x1)
    
    o#(m(a(x1))) = [0 4]x1 + [6] >= [0 4]x1 + [5] = t#(e(n(x1)))
    
    s#(a(x1)) = [2 4]x1 + [7] >= [2 4]x1 + [5] = t#(e(x1))
    
    s#(a(x1)) = [2 4]x1 + [7] >= [2 4]x1 + [4] = a#(t(e(x1)))
    
    s#(a(x1)) = [2 4]x1 + [7] >= [6] = o#(m(a(t(e(x1)))))
    
    s#(a(x1)) = [2 4]x1 + [7] >= [5] = t#(o(m(a(t(e(x1))))))
    
    s#(a(x1)) = [2 4]x1 + [7] >= [4] = a#(t(o(m(a(t(e(x1)))))))
    
    n#(s(x1)) = [2 2]x1 + [4] >= [0 2]x1 + [1] = t#(x1)
    
    n#(s(x1)) = [2 2]x1 + [4] >= [0 2]x1 = a#(t(x1))
    
    n#(s(x1)) = [2 2]x1 + [4] >= [2] = a#(l(a(t(x1))))
    
               [2 4]     [2]    [0 4]     [1]           
    t(o(x1)) = [0 0]x1 + [0] >= [0 0]x1 + [0] = m(a(x1))
    
               [2 4]     [4]    [2 2]     [4]           
    t(e(x1)) = [0 0]x1 + [0] >= [0 0]x1 + [0] = n(s(x1))
    
               [0 4]     [4]    [0 2]     [2]           
    a(l(x1)) = [0 0]x1 + [0] >= [0 0]x1 + [0] = a(t(x1))
    
                  [0 4]     [5]    [0 4]     [4]              
    o(m(a(x1))) = [0 4]x1 + [2] >= [0 0]x1 + [0] = t(e(n(x1)))
    
               [0 4]     [4]    [2]                             
    s(a(x1)) = [1 4]x1 + [4] >= [0] = l(a(t(o(m(a(t(e(x1))))))))
    
               [2 2]     [4]    [4]                 
    n(s(x1)) = [0 0]x1 + [0] >= [0] = a(l(a(t(x1))))
   problem:
    DPs:
     
    TRS:
     t(o(x1)) -> m(a(x1))
     t(e(x1)) -> n(s(x1))
     a(l(x1)) -> a(t(x1))
     o(m(a(x1))) -> t(e(n(x1)))
     s(a(x1)) -> l(a(t(o(m(a(t(e(x1))))))))
     n(s(x1)) -> a(l(a(t(x1))))
   Qed