MAYBE

Problem:
 +(1(),x) -> +(+(0(),1()),x)
 +(0(),x) -> x

Proof:
 DP Processor:
  DPs:
   +#(1(),x) -> +#(0(),1())
   +#(1(),x) -> +#(+(0(),1()),x)
  TRS:
   +(1(),x) -> +(+(0(),1()),x)
   +(0(),x) -> x
  Open