YES

Problem:
 f(g(X)) -> f(X)

Proof:
 DP Processor:
  DPs:
   f#(g(X)) -> f#(X)
  TRS:
   f(g(X)) -> f(X)
  Arctic Interpretation Processor:
   dimension: 2
   interpretation:
    [f#](x0) = [0 2]x0,
    
              [-4 3 ]     [0 ]
    [f](x0) = [1  2 ]x0 + [-&],
    
              [0  -&]     [-3]
    [g](x0) = [0  2 ]x0 + [3 ]
   orientation:
    f#(g(X)) = [2 4]X + [5] >= [0 2]X = f#(X)
    
              [3 5]    [6]    [-4 3 ]    [0 ]       
    f(g(X)) = [2 4]X + [5] >= [1  2 ]X + [-&] = f(X)
   problem:
    DPs:
     
    TRS:
     f(g(X)) -> f(X)
   Qed