YES Problem: a__f(X) -> g(h(f(X))) mark(f(X)) -> a__f(mark(X)) mark(g(X)) -> g(X) mark(h(X)) -> h(mark(X)) a__f(X) -> f(X) Proof: DP Processor: DPs: mark#(f(X)) -> mark#(X) mark#(f(X)) -> a__f#(mark(X)) mark#(h(X)) -> mark#(X) TRS: a__f(X) -> g(h(f(X))) mark(f(X)) -> a__f(mark(X)) mark(g(X)) -> g(X) mark(h(X)) -> h(mark(X)) a__f(X) -> f(X) Matrix Interpretation Processor: dim=4 interpretation: [mark#](x0) = [1 1 0 0]x0, [a__f#](x0) = [1 1 0 0]x0, [1 0 0 0] [0 1 0 0] [mark](x0) = [0 0 1 0]x0 [0 0 0 0] , [0 0 0 0] [0 0 1 0] [g](x0) = [0 0 0 0]x0 [0 0 0 0] , [0 0 0 0] [1] [1 1 0 0] [0] [h](x0) = [0 1 0 0]x0 + [0] [0 0 0 0] [0], [0 0 0 0] [0] [1 1 0 0] [1] [f](x0) = [0 0 0 0]x0 + [0] [0 0 0 0] [0], [0 0 0 0] [0] [1 1 0 0] [1] [a__f](x0) = [0 0 0 0]x0 + [0] [0 0 0 0] [0] orientation: mark#(f(X)) = [1 1 0 0]X + [1] >= [1 1 0 0]X = mark#(X) mark#(f(X)) = [1 1 0 0]X + [1] >= [1 1 0 0]X = a__f#(mark(X)) mark#(h(X)) = [1 1 0 0]X + [1] >= [1 1 0 0]X = mark#(X) [0 0 0 0] [0] [0 0 0 0] [0] [1 1 0 0] [1] [1 1 0 0] [1] a__f(X) = [0 0 0 0]X + [0] >= [0 0 0 0]X + [0] = g(h(f(X))) [0 0 0 0] [0] [0 0 0 0] [0] [0 0 0 0] [0] [0 0 0 0] [0] [1 1 0 0] [1] [1 1 0 0] [1] mark(f(X)) = [0 0 0 0]X + [0] >= [0 0 0 0]X + [0] = a__f(mark(X)) [0 0 0 0] [0] [0 0 0 0] [0] [0 0 0 0] [0 0 0 0] [0 0 1 0] [0 0 1 0] mark(g(X)) = [0 0 0 0]X >= [0 0 0 0]X = g(X) [0 0 0 0] [0 0 0 0] [0 0 0 0] [1] [0 0 0 0] [1] [1 1 0 0] [0] [1 1 0 0] [0] mark(h(X)) = [0 1 0 0]X + [0] >= [0 1 0 0]X + [0] = h(mark(X)) [0 0 0 0] [0] [0 0 0 0] [0] [0 0 0 0] [0] [0 0 0 0] [0] [1 1 0 0] [1] [1 1 0 0] [1] a__f(X) = [0 0 0 0]X + [0] >= [0 0 0 0]X + [0] = f(X) [0 0 0 0] [0] [0 0 0 0] [0] problem: DPs: TRS: a__f(X) -> g(h(f(X))) mark(f(X)) -> a__f(mark(X)) mark(g(X)) -> g(X) mark(h(X)) -> h(mark(X)) a__f(X) -> f(X) Qed