YES Problem: a__f(0()) -> cons(0(),f(s(0()))) a__f(s(0())) -> a__f(a__p(s(0()))) a__p(s(X)) -> mark(X) mark(f(X)) -> a__f(mark(X)) mark(p(X)) -> a__p(mark(X)) mark(0()) -> 0() mark(cons(X1,X2)) -> cons(mark(X1),X2) mark(s(X)) -> s(mark(X)) a__f(X) -> f(X) a__p(X) -> p(X) Proof: DP Processor: DPs: a__f#(s(0())) -> a__p#(s(0())) a__f#(s(0())) -> a__f#(a__p(s(0()))) a__p#(s(X)) -> mark#(X) mark#(f(X)) -> mark#(X) mark#(f(X)) -> a__f#(mark(X)) mark#(p(X)) -> mark#(X) mark#(p(X)) -> a__p#(mark(X)) mark#(cons(X1,X2)) -> mark#(X1) mark#(s(X)) -> mark#(X) TRS: a__f(0()) -> cons(0(),f(s(0()))) a__f(s(0())) -> a__f(a__p(s(0()))) a__p(s(X)) -> mark(X) mark(f(X)) -> a__f(mark(X)) mark(p(X)) -> a__p(mark(X)) mark(0()) -> 0() mark(cons(X1,X2)) -> cons(mark(X1),X2) mark(s(X)) -> s(mark(X)) a__f(X) -> f(X) a__p(X) -> p(X) Matrix Interpretation Processor: dim=3 interpretation: [mark#](x0) = [1 0 1]x0, [a__p#](x0) = [1 0 0]x0, [a__f#](x0) = [1 0 0]x0 + [1], [0 0 1] [0] [p](x0) = [0 0 1]x0 + [0] [1 0 0] [1], [mark](x0) = x0 , [0 0 1] [0] [a__p](x0) = [0 0 1]x0 + [0] [1 0 0] [1], [0 1 0] [0 1 0] [1] [cons](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [1 0 1] [0 0 0] [0], [1 1 1] [1] [f](x0) = [0 1 0]x0 + [0] [0 0 0] [1], [1 0 1] [1] [s](x0) = [0 0 0]x0 + [1] [1 1 0] [0], [1 1 1] [1] [a__f](x0) = [0 1 0]x0 + [0] [0 0 0] [1], [0] [0] = [0] [1] orientation: a__f#(s(0())) = 3 >= 2 = a__p#(s(0())) a__f#(s(0())) = 3 >= 1 = a__f#(a__p(s(0()))) a__p#(s(X)) = [1 0 1]X + [1] >= [1 0 1]X = mark#(X) mark#(f(X)) = [1 1 1]X + [2] >= [1 0 1]X = mark#(X) mark#(f(X)) = [1 1 1]X + [2] >= [1 0 0]X + [1] = a__f#(mark(X)) mark#(p(X)) = [1 0 1]X + [1] >= [1 0 1]X = mark#(X) mark#(p(X)) = [1 0 1]X + [1] >= [1 0 0]X = a__p#(mark(X)) mark#(cons(X1,X2)) = [1 1 1]X1 + [0 1 0]X2 + [1] >= [1 0 1]X1 = mark#(X1) mark#(s(X)) = [2 1 1]X + [1] >= [1 0 1]X = mark#(X) [2] [2] a__f(0()) = [0] >= [0] = cons(0(),f(s(0()))) [1] [1] [4] [4] a__f(s(0())) = [1] >= [0] = a__f(a__p(s(0()))) [1] [1] [1 1 0] [0] a__p(s(X)) = [1 1 0]X + [0] >= X = mark(X) [1 0 1] [2] [1 1 1] [1] [1 1 1] [1] mark(f(X)) = [0 1 0]X + [0] >= [0 1 0]X + [0] = a__f(mark(X)) [0 0 0] [1] [0 0 0] [1] [0 0 1] [0] [0 0 1] [0] mark(p(X)) = [0 0 1]X + [0] >= [0 0 1]X + [0] = a__p(mark(X)) [1 0 0] [1] [1 0 0] [1] [0] [0] mark(0()) = [0] >= [0] = 0() [1] [1] [0 1 0] [0 1 0] [1] [0 1 0] [0 1 0] [1] mark(cons(X1,X2)) = [0 0 0]X1 + [0 0 0]X2 + [0] >= [0 0 0]X1 + [0 0 0]X2 + [0] = cons(mark(X1),X2) [1 0 1] [0 0 0] [0] [1 0 1] [0 0 0] [0] [1 0 1] [1] [1 0 1] [1] mark(s(X)) = [0 0 0]X + [1] >= [0 0 0]X + [1] = s(mark(X)) [1 1 0] [0] [1 1 0] [0] [1 1 1] [1] [1 1 1] [1] a__f(X) = [0 1 0]X + [0] >= [0 1 0]X + [0] = f(X) [0 0 0] [1] [0 0 0] [1] [0 0 1] [0] [0 0 1] [0] a__p(X) = [0 0 1]X + [0] >= [0 0 1]X + [0] = p(X) [1 0 0] [1] [1 0 0] [1] problem: DPs: TRS: a__f(0()) -> cons(0(),f(s(0()))) a__f(s(0())) -> a__f(a__p(s(0()))) a__p(s(X)) -> mark(X) mark(f(X)) -> a__f(mark(X)) mark(p(X)) -> a__p(mark(X)) mark(0()) -> 0() mark(cons(X1,X2)) -> cons(mark(X1),X2) mark(s(X)) -> s(mark(X)) a__f(X) -> f(X) a__p(X) -> p(X) Qed