MAYBE

Problem:
 f(0(),1(),x) -> f(x,x,x)
 f(x,y,z) -> 2()
 0() -> 2()
 1() -> 2()

Proof:
 DP Processor:
  DPs:
   f#(0(),1(),x) -> f#(x,x,x)
  TRS:
   f(0(),1(),x) -> f(x,x,x)
   f(x,y,z) -> 2()
   0() -> 2()
   1() -> 2()
  Open