MAYBE

Problem:
 f(x,f(y,a())) -> h(f(a(),f(f(x,a()),y)))

Proof:
 DP Processor:
  DPs:
   f#(x,f(y,a())) -> f#(x,a())
   f#(x,f(y,a())) -> f#(f(x,a()),y)
   f#(x,f(y,a())) -> f#(a(),f(f(x,a()),y))
  TRS:
   f(x,f(y,a())) -> h(f(a(),f(f(x,a()),y)))
  Open